Print a pattern no restriction for language ..

Question

Shivam Agrawal (shivamagrawal726@gmail.com) · Accepted Answer

#include

int main() {
   int i,j;
   for (i=1;i=6-i && j<=9-i){
               printf("*");
           }
           else{
               printf(" ");
           }
       }
       printf("
");
   }
}

output:
    ****
   **** 
  ****  
 ****   
****

Anonymous · Answer

#include

int main() {
   int i,j;
   for (i=1;i=6-i && j<=9-i){
               printf("*");
           }
           else{
               printf(" ");
           }
       }
       printf("
");
   }
}

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