Microsoft interview question
Find the first duplicate in an unordered list
Interview Answer
Anonymous
19 Mar 2018
list 1 = [1,4,1,2,3] list 2 =[] for i in list1: if i not in list2: list2.append(i) else print(i) print('first duplicate') break:
Find the first duplicate in an unordered list
Anonymous
list 1 = [1,4,1,2,3] list 2 =[] for i in list1: if i not in list2: list2.append(i) else print(i) print('first duplicate') break:
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